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5x^2+4x+20=10
We move all terms to the left:
5x^2+4x+20-(10)=0
We add all the numbers together, and all the variables
5x^2+4x+10=0
a = 5; b = 4; c = +10;
Δ = b2-4ac
Δ = 42-4·5·10
Δ = -184
Delta is less than zero, so there is no solution for the equation
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